Final answer:
Using the physics equation of motion for free fall and neglecting air resistance, a penny dropped from a 320-meter-high building would hit the ground at approximately 79.2 m/s.
Step-by-step explanation:
To find the speed at which the penny is traveling when it hits the ground after being dropped from a 320-meter-high building, we would use the principles of physics, specifically kinematics and the equations of motion for an object in free fall.
Assuming no air resistance, the speed of the penny when it strikes the ground can be calculated using the following equation of motion:
v = √(2gh)
where:
v is the final velocity,
g is the acceleration due to gravity (9.81 m/s² on Earth), and
h is the height from which the penny is dropped (320 m).Plugging withinside the values, we get:
v = √(2 * 9.81 m/s² * 320 m) = √(6272) m²/s² ≈ 79.2 m/s
So the penny would be traveling at approximately 79.2 m/s when it hits the ground if air resistance is neglected.