Question

If f(x) = x^2 + 1 find f (a+1)

Answer 1

`{ \tt{f(x) = {x}^(2) + 1 }} \\ { \tt{f(a + 1) = {(a + 1)}^(2) + 1 }} \\ { \tt{f(a + 1) = ( {a}^(2) + 2a + 1) + 1 }} \\ { \tt{f(a + 1) = {a}^(2) + 2a + 2}}`

Answer 2

f(a + 1) = a² + 2a + 2

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

• Terms/Coefficients
• Functions
• Function Notation
• Expand by FOIL

Explanation:

Step 1: Define

Identify

f(x) = x² + 1

Step 2: Evaluate

1. Substitute in x [Function f(x)]: f(a + 1) = (a + 1)² + 1
2. Expand [FOIL]: f(a + 1) = a² + 2a + 1 + 1
3. Combine like terms: f(a + 1) = a² + 2a + 2