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What is the unit distance, rounded to the nearest tenth, between the points (-2, 4) and (6, -2)?

User Kylo
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5 votes

Answer:

formule :


√(x2-x1)^2 + (y2-y1)^2) =\\\\√((6-(-2))^2+(-2-4)^2) =\\\\√(8^2+6^2) = √(100) \\\\

→√100 = 10

→The distance between the points (-2, 4) and (6, -2) is therefore 10, rounded to the nearest tenth.

User Franbenz
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