Final answer:
The question is related to Physics, where we use the conservation of energy and the impulse-momentum theorem to calculate the force exerted by a falling hammer on a nail.
Step-by-step explanation:
The subject of the question is Physics, specifically relating to concepts of mechanics and impulse.
Given a hammer weighing 100N falls from a height of 1.25m and the impact lasts for 0.01 seconds (10-2 sec), we are asked to calculate the force of the blow of the impact.
To calculate the force exerted by the hammer during the impact, we can use the formula F = Δp / Δt, where F is the force, Δp is the change in momentum, and Δt is the change in time.
First, we find the velocity of the hammer just before the impact using the energy conservation principle, where potential energy is converted into kinetic energy (mgh = 1/2 mv2).
With the velocity (v), we can calculate the hammer's momentum (p = mv) just before it hits the nail.
The hammer comes to a rest upon impact, making its final momentum zero. The change in momentum (Δp) would be the initial momentum. Put this value into the impulse equation with the given time to find the force (F).