Question

When a 200-byte message is sent at 100 Kbps by using a 10 km cable with a propagation speed of 2× 10⁸ m/sec, which of the following is the total delay in milliseconds? Here, the total delay can be defined as the sum of the transmission and propagation delays, and there is no processing delay.

a) 2.00 b) 2.05 c) 16.00 d) 16.05​

Answer 1

Answer: (b) "2.05

Explanation:

To calculate the total delay for sending a 200-byte message over a 10 km cable with a propagation speed of 2 × 10^8 m/s at a transmission rate of 100 Kbps, we need to consider both transmission delay and propagation delay.

First, let's calculate the transmission delay:

Transmission Delay (Td) = Size of Message (in bits) / Transmission Rate (in bps)

Transmission Delay (Td) = (200 bytes × 8 bits/byte) / 100,000 bps

Transmission Delay (Td) = 1600 bits / 100,000 bps

Transmission Delay (Td) = 0.016 seconds (or 16 milliseconds)

Now, let's calculate the propagation delay:

Propagation Delay (Pd) = Cable Length / Propagation Speed

Propagation Delay (Pd) = 10,000 meters / (2 × 10^8 m/s)

Propagation Delay (Pd) = 0.05 seconds (or 50 milliseconds)

Now, we can calculate the total delay:

Total Delay = Transmission Delay + Propagation Delay

Total Delay = 0.016 seconds + 0.05 seconds

Total Delay = 0.066 seconds (or 66 milliseconds)

So, the total delay in milliseconds is 66 milliseconds. None of the provided options match this result exactly. The option is option (b) "2.05,"is the correct answer.