Answer:
Perimeter of larger square = 64 cm
Explanation:
Let the side of one square be 'x'.
The side of other square = (x + 3) cm

Finding the area of each square:
Area of square1 = x*x = x²
Area of square2 = (x+3) (x +3)
= (x + 3)²
Use algebraic identity (a + b)² = a² + 2ab + b²
= x² + 2*x*3 + 3²
= x² + 6x + 9
Factorizing the polynomials:
Sum of two squares = 549 cm²
x² + x² + 6x + 9 = 549
Combine like terms,
2x² + 6x + 9 = 549
2x² + 6x + 9 - 549 = 0
2x² + 6x - 540 = 0
Divide the entire equation by 2,
x² + 3x - 270 = 0
Sum = 3
Product = -270
Factors = 18 , (-15)
When we add 18 and (-15), we get 3 and when we multiply (-15) & 18, we get -270.
Rewrite the middle term using the factors.
x² + 18x -15x - 270 = 0
x(x + 18) - 15(x + 18) = 0
(x + 18)(x - 15) = 0
x + 18 = 0
x = -18 {Ignore as side of square cannot be a negative number}
x - 15 = 0
x = 15
Perimeter of larger square:
side = x + 3 = 15 + 3
= 18 cm
Perimeter of larger square = 4 * 18
= 64 cm
Answer: Perimeter of larger square = 64 cm