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Find the work done by the force f=5i+25j in moving an object from p(0,0) to q(1,6)

User Randomx
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Final answer:

The work done by the force f=5i+25j in moving the object from p(0,0) to q(1,6) is 155 units of work.

Step-by-step explanation:

To find the work done by a force, we can use the dot product of the force vector and the displacement vector. The dot product is given by:


W = F · Δr

Where F is the force vector and Δr is the displacement vector.


In this case, the force vector is f = 5i + 25j and the displacement vector Δr = q - p = (1-0)i + (6-0)j = i + 6j.

Now, we can calculate the dot product:

W = (5i + 25j) · (i + 6j) = 5*1 + 25*6 = 155

Therefore, the work done by the force f=5i+25j in moving the object from p(0,0) to q(1,6) is 155 units of work.

Learn more about Work done by a force

User Soribel
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