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85.1 J of energy are added to a 4.29 gram sample of copper. If the final temperature of the copper was 75.4 °C, what was the initial temperature in Celsius? The specific heat capacity of copper is 0.385 J*g^-1*°C^-1

User Willjay
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1 Answer

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Step-by-step explanation:

85.1 J / (4.29 g * ( 75.4 - i °C )) = .385 J g / C

Solve for i = initial temp °C

i = 23.9 °C

User Boeledi
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