Answer:
x = 2 and x = -4
Explanation:
To find the solutions to the quadratic equation 3x^2 + 6x - 24 = 0, you can use the quadratic formula, which is given by:
x = (-b ± √(b² - 4ac)) / (2a)
In this equation, a = 3, b = 6, and c = -24. Plug these values into the quadratic formula:
x = (-6 ± √(6² - 4 * 3 * (-24))) / (2 * 3)
Now, calculate the values inside the square root and simplify:
x = (-6 ± √(36 + 288)) / 6
x = (-6 ± √324) / 6
x = (-6 ± 18) / 6
Now, consider both the positive and negative square root solutions:
x = (-6 + 18) / 6
x = 12 / 6
x = 2
x = (-6 - 18) / 6
x = -24 / 6
x = -4
So, the solutions to the equation 3x^2 + 6x - 24 = 0 are x = 2 and x = -4.