Final answer:
To find the height a ball was dropped from, you use the equation of motion for free falling: s = ut + 0.5gt². Substituting 5 seconds for 't', 9.8 m/s² for 'g', and noting that 'u' equals 0 (the ball was dropped from rest), you get s = 0*5 + 0.5*9.8*5². Solving, you find that 's' equals approximately 123 metres, which is the height the ball was dropped from.
Step-by-step explanation:
This problem pertains to physics, specifically it involves the concept of free falling objects and requires the use of the equation of motion where acceleration due to gravity is taken into account. In situations like this, we consider acceleration due to gravity (g) as 9.8 m/s².
To determine the height from which the ball was dropped, we use the following equation: s = ut + 0.5gt². In this scenario, 'u' (the initial velocity) equals 0, because the ball is dropped from rest, 't' (time) equals 5 seconds, and 'g' (acceleration due to gravity) equals 9.8 m/s².
Substitute those values into the equation to get: s = 0*5 + 0.5*9.8*5². Solving the equation, you find that the height 's' is approximately 123 metres, which is the height from which the ball was dropped.
Learn more about Free Falling Objects