37.3k views
3 votes
Recursive rule in Arithmetic.

Recursive rule in Arithmetic.-example-1
User TchPowDog
by
7.6k points

1 Answer

3 votes

Answer: "a" must be less than or equal to -6/5 for the inequality to be true.

Explanation:

The inequality you provided is:

a >= a(7 - 1) + 6

First, let's simplify the right-hand side of the inequality:

a(7 - 1) is equal to 6a, as 7 - 1 = 6.

So, the inequality becomes:

a >= 6a + 6

Next, we'll subtract 6a from both sides of the inequality to isolate "a" on one side:

a - 6a >= 6

This gives us:

-5a >= 6

Now, to solve for "a," we need to divide both sides of the inequality by -5. However, when you divide by a negative number, remember that the direction of the inequality is reversed:

a <= -6/5

Therefore, the solution to the inequality is:

a <= -6/5

This means that "a" must be less than or equal to -6/5 for the inequality to be true.

User Nuncjo
by
7.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories