88.7k views
1 vote
Is the square root of a number always larger than the cube root of that number?

User Sif
by
8.4k points

2 Answers

3 votes

Answer:

The square root of a number is mostly always larger.

For example,

√25 =5 and ∛25≈2.92 5>2.92

√5879≈76.67 and ∛≈18.05 76.67>18.05

It works for those examples, but what if we use smaller numbers?

√1=1 and ∛1=1 1=1

√0=0 and ∛0=0 0=0

So, the square root of a number is larger than the cube root of a number, except in some cases when they are equal to each other.

User Morteza Manavi
by
8.0k points
2 votes
Yes, always except when that number is 0 or 1. Take the number 64 for example. The square root of that is 8. The cubes root of that is 4. This is sense 8^2=64. So to raise the exponent the base must be smaller. Therefore a square root of a number will always be larger than the cubed root of it. Of course expect when the number is 1 or 0 as it doesn’t matter if it’s cubed or square root. It will still be 1 or 0
User Charelle
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories