Final answer:
The multiplication of all odd numbers from 1 to 99, inclusive, yields a result ending in 25 because every 10th number ends with either 5, or with an odd number, and multiplicating any number with a number ending in 5 gives a result ending in 5, which carries forward.
Step-by-step explanation:
This is a question pertaining to properties of numbers in Mathematics. Specifically, it focuses on finding the last two digits of a product of all odd numbers from 1 to 99. You might think it involves a lot of multiplication, which could be daunting. But, there's a very simple way to figure this out by using repeated patterns and focusing on the unit digit.
Consider all odd numbers from 1 to 99, inclusive. What you notice is that every 10th number ends with either 5 (for the numbers in the 5-15-25.. series) or with an odd number (for the numbers in the 1-11-21... series). The multiplication of any number with an odd number ending with 5 yields a result ending in 5... which then carries to the next value, repeating the cycle.
Therefore, the last two digits of the multiplication of all these numbers will end in 25. That is option B).
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