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Find the perimeter of a triangle whose sides are 5 1/2 cm, 7 3/5 cm, and 3 1/4 Cm respectively.

User Stephenie
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2 Answers

3 votes

Answer:


16(7)/(20)

Explanation:

All you need to do is add all of the sides together.


5(1)/(2) +
7(3)/(5) +
3(1)/(4) =
16(7)/(20)

User YSR Fan
by
7.7k points
6 votes

To find the perimeter of a triangle, you need to add up the lengths of all three sides.

Given the lengths of the sides as 5 1/2 cm, 7 3/5 cm, and 3 1/4 cm respectively, we can add them together to find the perimeter.

5 1/2 cm + 7 3/5 cm + 3 1/4 cm

To add these mixed numbers, we first convert them to improper fractions:

5 1/2 cm = 11/2 cm

7 3/5 cm = 38/5 cm

3 1/4 cm = 13/4 cm

Now, we can add the fractions:

11/2 cm + 38/5 cm + 13/4 cm

To add fractions with different denominators, we need to find a common denominator. In this case, the least common multiple of 2, 5, and 4 is 20.

So, let's rewrite the fractions with a common denominator of 20:

11/2 cm = 110/20 cm

38/5 cm = 152/20 cm

13/4 cm = 65/20 cm

Now, we can add the fractions:

110/20 cm + 152/20 cm + 65/20 cm = 327/20 cm

Finally, we simplify the fraction:

327/20 cm = 16 7/20 cm

Therefore, the perimeter of the triangle is 16 7/20 cm.

User Stephen Peterson
by
9.0k points

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