Question

Please help!!!!! college alg

Answer 1

`\begin{array}{llll} f(x)~from\\\\ x_1 ~~ to ~~ x_2 \end{array}~\hfill slope = m \implies \cfrac{ \stackrel{rise}{f(x_2) - f(x_1)}}{ \underset{run}{x_2 - x_1}}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array} \\\\[-0.35em] ~\dotfill`

`f(x)= x^{(1)/(3)} \qquad \begin{cases} x_1=-4\\ x_2=5 \end{cases}\implies \cfrac{f(5)-f(-4)}{5 - (-4)} \\\\\\ \cfrac{5^{(1)/(3)}~~ - ~~(-4)^{(1)/(3)}}{5+4}\implies \cfrac{\sqrt[3]{5}+\sqrt[3]{-4}}{9} ~~ \approx ~~ \cfrac{0.1225748947084974}{9} ~~ \approx ~~\text{\LARGE 0.0136}`