Question

A flat sheet of paper of area 0.100 m2 is oriented so that the normal to the sheet is at an angle of 64 ∘ to a uniform electric field of magnitude 19 N/C .

Answer 1

It seems you're describing a situation involving an electric field and a flat sheet of paper. To calculate the electric flux through the paper, you can use the formula:

Electric Flux (Φ) = Electric Field (E) × Area (A) × cos(θ)

Where:
- Electric Flux (Φ) is measured in N·m²/C (or Volts·m)
- Electric Field (E) is measured in N/C
- Area (A) is measured in m²
- θ is the angle between the electric field direction and the normal to the surface (in degrees)

In your case:
- Electric Field (E) = 19 N/C
- Area (A) = 0.100 m²
- θ = 64°

Now, plug these values into the formula:

Φ = (19 N/C) × (0.100 m²) × cos(64°)

Calculate the cosine of 64°:

cos(64°) ≈ 0.4384

Now, calculate the electric flux:

Φ ≈ (19 N/C) × (0.100 m²) × 0.4384 ≈ 0.8304 N·m²/C

So, the electric flux through the paper is approximately 0.8304 N·m²/C.