Question

A smooth wooden block is placed on a smooth wooden tabletop. You must exert a 14.0N force to keep the 40.0N block moving at constant velocity. a. What is the coefficient of sliding friction? b. If a 20.0N brick is placed on the block, what force will be required to keep the block and brick moving at constant velocity?

Answer 1

The coefficient of sliding friction is 0.35. The force required to keep the block and brick moving at constant velocity is 21.0N.

Step-by-step explanation:

In order to find the coefficient of sliding friction, we can use the formula:

coefficient of sliding friction = force of friction / normal force

In this case, the force of friction is equal to the force you exert to keep the block moving at constant velocity, which is 14.0N. The normal force is equal to the weight of the block, which is 40.0N. Therefore, the coefficient of sliding friction is:

coefficient of sliding friction = 14.0N / 40.0N = 0.35

To find the force required to keep the block and brick moving at constant velocity with a 20.0N brick added, we can use the same formula:

force of friction = coefficient of sliding friction * normal force

The normal force in this case is the combined weight of the block and the brick, which is 40.0N + 20.0N = 60.0N. Therefore, the force required to keep the block and brick moving at constant velocity is:

force of friction = 0.35 * 60.0N = 21.0N

Learn more about Coefficient of sliding friction