Final answer:
The normality of a 0.5M Na2CO3 solution is calculated by multiplying the molarity by the number of equivalents. Since one molecule of Na2CO3 yields two equivalents, the normality would be 1N.
Step-by-step explanation:
To calculate the normality of a 0.5M Na2CO3 solution, you must first understand that normality (N) refers to the number of equivalent weights of a solute per liter of solution. Now, Na2CO3 (sodium carbonate) is a salt with one molecule containing two Na+ ions. Therefore, this compound can be dissociated into two equivalents per molecule.
Therefore, to calculate normality, the molarity needs to be multiplied by the number of equivalents. In this case, the normality would be 0.5M * 2 (since there are two Na+ ions in one Na2CO3 molecule yielding two equivalents), which equals 1N.
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