151k views
3 votes
Solve the following elementary exponential equation. ((1/3)^3x+7))=(1/9)^4

User Trissa
by
7.4k points

1 Answer

5 votes

Final answer:

To solve the equation, ((1/3)^(3x+7))=(1/9)^4, we simplify both sides and apply the exponent rule. After equating the exponents, we solve for x by isolating it. The solution is x = 1/3.

Step-by-step explanation:

To solve the equation ((1/3)^{3x+7})=(1/9)^4, we need to first simplify both sides of the equation. We can simplify the left side by applying the exponent rule that states (a^b)^c = a^(b*c). Applying this rule, we can write the equation as (1/3)^(3x+7) = (1/3)^(4*2).

Now that the bases are the same, we can equate the exponents. So, 3x + 7 = 4*2. Simplifying further, 3x + 7 = 8.

To solve for x, we subtract 7 from both sides of the equation, giving us 3x = 1. Finally, we divide both sides by 3 to isolate x, resulting in x = 1/3.

Learn more about Solving exponential equations

User Dejohn
by
8.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.