Final answer:
To solve the system of linear equations, we can use row operations to transform the augmented matrix into reduced row echelon form. The solution to the system of equations is x = 0 and y = -2.11.
Step-by-step explanation:
To solve the system of linear equations, we can write the augmented matrix using the coefficients of the variables and constant terms. The augmented matrix for the given system is:
| -5 10 -30 |
| -6 17 21 |
To reduce the matrix to its row echelon form, we can perform row operations. The goal is to transform the matrix into an upper triangular form. Here are the steps:
- Multiply the first row by 6 and the second row by 5, then add the second row to the first row:
- | -30 60 -180 ||
- 0
- 85 -179 |
- Divide the second row by 85 to make the leading coefficient 1:
- | -30 60 -180 || 0
- 1
- -2.11 |
- Multiply the second row by -60 and add it to the first row:
- |
- 0
- 0 0 || 0 1 -2.11 |
The matrix is now in reduced row echelon form. The solution to the system of equations is x = 0 and y = -2.11.
Learn more about Solving systems of linear equations