To find three points on the line with a slope of 1/2 that passes through the point (5, 4), you can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Where:
(x1, y1) is the given point (5, 4).
m is the slope, which is 1/2.
Plug in the values:
y - 4 = (1/2)(x - 5)
Now, you can find three points by selecting different x-values and solving for the corresponding y-values:
Let's choose x = 6:
y - 4 = (1/2)(6 - 5)
y - 4 = 1/2
y = 4 + 1/2
y = 9/2
So, one point on the line is (6, 9/2), which is the same as (6, 4.5).
Let's choose x = 7:
y - 4 = (1/2)(7 - 5)
y - 4 = 1
y = 4 + 1
y = 5
Another point on the line is (7, 5).
Let's choose x = 8:
y - 4 = (1/2)(8 - 5)
y - 4 = 3/2
y = 4 + 3/2
y = 11/2
The third point on the line is (8, 11/2), which is the same as (8, 5.5).
So, three points on the line with a slope of 1/2 that passes through (5, 4) are (6, 4.5), (7, 5), and (8, 5.5).