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Find the perimeter of a right triangle, given that one of the side lengths is 5 and the length of the hypotenuse is 14. Round your answer to the nearest hundredth.

User Elior
by
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2 Answers

0 votes

Answer:

32.08

Explanation:

Formula to find any side length of a right triangle:

a^2 + b^2 = c^2

Where "a" and "b" represent legs/sides of a right triangle and "c" represents the hypotenuse, the longest side.

Plug in the side lengths and hypotenuse into this formula:

a^2 + b^2 = c^2

(5)^2 + b^2 = (14)^2

Solve, by finding exponents first:

25 + b^2 = 196

Get the variable, b, alone by subtracting 25 from both sides because the inverse operation of addition is subtraction:

25 + b^2 = 196

-25 -25

b^2 = 171

Square both sides since the inverse operation of squaring is finding the square root:

b^2 = 171


√(b^2) =
√(171)

*Square root and squaring cancel out*

b = √171

Which is,

b = 13.0766968306

Round to the nearest hundredth:

b ≈ 13.08

Let's check our answer just in case:

a^2 + b^2 = c^2

5^2 + 13.08^2 = 14^2

25 + 171.1 = 196

196.1 ≈ 196

They are about the same, so 13.08 for one of the side lengths is correct.

Now let's find the perimeter by adding all the side lengths together:

5 + 13.08 + 14

= 32.08 is the perimeter.

User DannyLane
by
8.3k points
2 votes

Answer:

perimeter

Explanation:

don't know as well

User Jamiela
by
8.3k points

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