Question

In a circle, the endpoints of a diameter are (3, 7) and (-5, 3). What is the center of the circle?

Answer 1

`\textsf{The midpoint of diameter is the center of the circle.}\\\textsf{So, here we need to find the midpoint of line (diameter) joining (3,7) and (-5,3).}\\\textsf{Let the center of circle be (h,k).}\\ \textsf{Then, from the midpoint formula we have:}\\`

`\sf\\(h,k)=((3-5)/(2),(7+3)/(2))=(-1,5)`

`\textsf{So the center of the circle is (-1,5).}`