Question

Mia and Ryan are selling raffle tickets during a basketball game. Mia has sold seven less than twice the number of tickets that Ryan has sold. If they have sold 80 tickets altogether, how many more tickets has Mia sold than Ryan? A. 22 B. 23 C. 24 D. 25

Answer 1

Mia has sold 22 more tickets than Ryan.

Step-by-step explanation:

Let's assume that Ryan has sold x number of tickets. According to the information given, Mia has sold seven less than twice the number of tickets sold by Ryan. So, Mia has sold 2x - 7 tickets. The total number of tickets sold by both Mia and Ryan is 80, so we can write the equation as:

x + (2x - 7) = 80

Combining like terms, we get 3x - 7 = 80. Adding 7 to both sides, we get 3x = 87. Dividing both sides by 3, we get x = 29.

Therefore, Ryan has sold 29 tickets and Mia has sold 2(29) - 7 = 51 tickets. To find out how many more tickets Mia has sold than Ryan, we subtract Ryan's number of tickets from Mia's number of tickets: 51 - 29 = 22.

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