Question

The length of a room is 5 more than twice its width. If the total perimeter is 40 meters, what is the width of the room? Simplify the following expression:

Answer 1

width = 5 m

Explanation:

let the width of the room be w then the length = 2w + 5 ( that is 5 more than twice its width )

perimeter is the sum of the sides

for a rectangular room the perimeter is calculated as

perimeter = 2 ( length + width ) = 2(2w + 5 + w) = 2(3w + 5)

given the perimeter is 40 m , then equating

2(3w + 5) = 40 ( divide both sides by 2 )

3w + 5 = 20 ( subtract 5 from both sides )

3w = 15 ( divide both sides by 3 )

w = 5

that is the width of the room is 5 m