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Find the area and perimeter.

A.63x^2 + 16; 22x + 14
B.18x^2 + 63x; 16x + 2
C.18x^2 + 63x; 22x + 14
D.63x^2 + 18; 11x + 7

Find the area and perimeter. A.63x^2 + 16; 22x + 14 B.18x^2 + 63x; 16x + 2 C.18x^2 + 63x-example-1
User Staxim
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1 Answer

2 votes

Hello!

Answer:

The answer is C.


\Large \boxed{ \sf P =14 + 22x}


\Large \boxed{ \sf A= 18x^2 + 63x}

Explanation:

→ We want to calculate the area and the perimeter of this rectangle:

I I
I I 2x + 7
I I
I I
I I

9x

→ We know that:

- the perimeter is equal to
\sf P = 2(l+w)

- the area is equal to
\sf A = l * w

Where:

- P is the perimeter

- A is the area

- l is the lenght

- w is the width

→ Let's apply these formula:


\sf P = 2(l+w) \\\\= 2(2x+7 + 9x)\\\\= 2(7+11x)\\\\\boxed{ \sf= 14 + 22x}


\sf A = l * w\\\\= (2x+7) * 9x\\\\= 9x(2x+7)\\\\\boxed{ \sf = 18x^2 + 63x}

Conclusion:

The perimeter is equal to 14 + 22x.

The area is equal to 18x² + 63x.

→ So the correct answer is C.

User Xelnor
by
7.8k points

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