Answer:
To solve for k in the equation:
(k + 6)/3 = (k + 4)/2
First, we can cross multiply to eliminate the fractions:
2(k + 6) = 3(k + 4)
Expanding the terms:
2k + 12 = 3k + 12
Now, let's isolate the k term on one side of the equation:
2k - 3k = 12 - 12
-k = 0
Finally, we divide both sides by -1 to solve for k:
k = 0
Therefore, the solution to the equation is k = 0.