Question

An object is thrown upward from a platform. The height of the object above the ground in feet is given by the function h(t)=-16t^(2)+64t+25, where t represents the time in seconds since the object was thrown. What is the maximum height the object will reach?

Answer 1

Step-by-step explanation:

`h = { - 16t}^(2) + 64t + 25`

`(dh)/(dt) = - 32t + 64`

to find the time taken to reach maximum height.

`- 32t + 64 = 0 \\ t = 2s`

so the time taken to reach maximum height is 2 seconds.

how to find maximum height the object would reach.

`h = { - 16(2)}^(2) + 64(2) + 25 \\ h = 89 \: meters`

therefore the height reached by the object is 89 m.