185k views
1 vote
Line C is perpendicular (negate and reciprocate ) to Line A and passes through (4,-6).

Write this equation in point slope form.

User Bohr
by
8.2k points

1 Answer

3 votes

Final answer:

To write the equation of Line C in point slope form, we use the perpendicularity of Line C and Line A and the given point (4,-6). We find the slope of Line C by taking the negative reciprocal of the slope of Line A. Substituting the point and the slope into the point-slope form equation gives us the equation y + 6 = -1/m(x - 4).

Step-by-step explanation:

To write the equation of a line in point-slope form, we need a point on the line and the slope of the line. In this case, the point given is (4, -6). Since line C is perpendicular to line A, the slopes of the two lines are negative reciprocals of each other. Let's assume the slope of line A is m. The slope of line C is then -1/m.

Now, let's substitute the point (4, -6) and the slope -1/m into the point-slope form equation y - y1 = m(x - x1). We get: y - (-6) = -1/m(x - 4), which simplifies to y + 6 = -1/m(x - 4).

Therefore, the equation of line C in point-slope form is: y + 6 = -1/m(x - 4).

Learn more about Equations of Lines

User Vvg
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories