Question

In a bowl of M &e M candies, (1)/(4) are green,, (1)/(3) are red, (1)/(6) are yellow and (1)/(12) are brown, what fractional part remains?

Answer 1

1/6 remains

Explanation:

1 - (1/4 + 1/3 + 1/6 + 1/12)

1 - (3/12 + 4/12 + 2/12 + 1/12) Rewrite the fractions with common denominators

1/4 x 3/3 = 3/12

1/3 x 4/4 = 4/12

1/6 x 2/2 = 2/12

1/12

1 - (10/12) Another name for 1 = 12/12

12/12 - 10/12 = 2/12

2/12 ÷ 2/2 = 1/6