Answer:
1, x=(24/27)
2. The width (x) is = 7 cm
3. 1163456 (Assuming the value given for π is correct)
4. R= (I-W2L2E)/2, assuming "R2" is "2R."
Explanation:
1. 32x−1−23−x=4x
31x-24=4x
27x = 24
x = (24/27)
2. Let x be the width of the rectangle. It's length would be 3x ("three times as long as it is wide').
We can write:
w = x , and
l = 3x
The perimeter of a rectangle is 2w + 2l, where w and l are width and length, respectively.
Perimeter: 2w + 2l = 56 cm
Now use the values of w and l derived above:
2w + 2l = 56 cm
2(x) + 2(3x) = 56 cm
8x = 56 cm
x = 7 cm
The width (x) is = 7 cm
CHECK:
Width = 7 cm
Length = 21 cm
Perimeter = 2*7 cm + 2*21 cm
Perimeter = (14 + 42) cm
Perimeter = 56 cm
3. Find the value of 2πgl when π=371,1=98 and g=32
2πgl
2πgl = 2*(371)(32)(98)
2πgl = 1163456
4. I=R2+W2L2E
-R2=-I+W2L2E
-R= (-I+W2L2E)/2
R= - (-I+W2L2E)/2
R= (I-W2L2E)/2