Question

A solution of NaOH is standardized by titration with 0.100 N HCl. A total of 10.0 mL of NaOH requires 11.25 ml of HCl. What is the normality of the NaOH solution?

Answer 1

The normality of the NaOH solution is calculated through titration with HCl, using the formula 'N1V1 = N2V2'. Given the normality of HCl and the volumes of both solutions, the normality of the NaOH solution is calculated to be 0.1125 N.

Step-by-step explanation:

In chemistry, the concept of normality refers to the gram equivalent weight of a solute per liter of solution. It is used in titration calculations. Titration is a chemical process to determine the concentration of a particular solution, in this case, NaOH (Sodium Hydroxide).

Given that the normality of HCl (Hydrochloric acid) is 0.100 N and the volume of the HCl needed is 11.25 mL, and assuming the reaction between NaOH and HCl is in a 1:1 ratio, the normality of the NaOH solution can be calculated using the formula 'N1V1 = N2V2' where N refers to Normality and V to Volume.

In this case, HCl is N1, the volume of HCl is V1 (0.01125 L), NaOH is N2, and the volume of NaOH is V2 (0.01 L). By substituting the values in the formula, we get N2 = (N1V1) / V2 = (0.100 * 0.01125) / 0.01 = 0.1125 N. Hence, the normality of the NaOH solution is 0.1125 N.

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