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The solution for \( x \) of the equation \( 8 e^{x}-1=0 \) is

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Answer:

Explanation:

The equation \(8e^x - 1 = 0\) can be solved to find the value of \(x\).

To solve for \(x\), we need to isolate the exponential term, \(e^x\).

Here are the steps to solve the equation:

1. Add 1 to both sides of the equation to isolate the exponential term:

\(8e^x = 1\)

2. Divide both sides of the equation by 8:

\(\frac{{8e^x}}{8} = \frac{1}{8}\)

3. Simplify:

\(e^x = \frac{1}{8}\)

4. To solve for \(x\), we can take the natural logarithm (ln) of both sides of the equation:

\(\ln(e^x) = \ln\left(\frac{1}{8}\right)\)

5. Since \(\ln(e^x)\) and \(e^x\) are inverse functions, they cancel each other out:

\(x = \ln\left(\frac{1}{8}\right)\)

6. Use the properties of logarithms to simplify further:

\(x = \ln(1) - \ln(8)\)

7. Simplify:

\(x = -\ln(8)\)

Therefore, the solution for \(x\) in the equation \(8e^x - 1 = 0\) is \(x = -\ln(8)\).

User Abdelaziz Dabebi
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