Final answer:
Marta's larger square, which has dimensions twice that of the original 4-inch square, results in an area that is four times greater. The original square's area is 16 square inches, while the larger square's area is 64 square inches.
Step-by-step explanation:
The question mentions that Marta has an original square with a side length of 4 inches. She also has a similar square whose dimensions are twice that of the first square.
To find the area of the larger square, we use the scale factor, which is 2 in this case. This means that each side of the larger square is 4 inches × 2, resulting in side lengths of 8 inches.
Now, to compare the areas of the two squares, we use the formula for the area of a square, which is side length squared (A = s²). Therefore, the area of the smaller square is 4 inches × 4 inches = 16 square inches. The area of the larger square is 8 inches × 8 inches = 64 square inches.
Comparing the two areas, the larger square's area is 64 square inches which is four times the area of the smaller square (16 square inches). This illustrates that when scaling up the dimensions of a figure by a factor of 2, the area increases by a factor of 2², or 4.