Answer:
(3x−2y+5z)
2
as shown below:
=(3x)
+(−2y)
+(5z)
+(2×3x×(−2y))+(2×(−2y)×5z)+(2×5z×3x)
(∵(a+b+c)
=a
+b
+c
+2ab+2bc+2ca)
=9x
+4y
+25z
−12xy−20yz+30zx
Hence, (3x−2y+5z)
−12xy−20yz+30zx.
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