Final answer:
Without specific details on the triangle, the double integral of 2ye^x over a triangular region involves setting up the integral with appropriate limits and integrating first with respect to y and then x.
Step-by-step explanation:
To calculate the double integral of f(x,y) = 2ye^x over a triangular region, we need to set up the integral bounds based on the coordinates of the triangle's vertices. Assuming the triangle vertices are given or can be deduced from the context (which was not provided in the question), you would typically integrate with respect to y first from a linear function (or constant) to another linear function, and then integrate with respect to x from the lowest x-value of the triangle to the highest.
The double integral will be in the form:
\[ \int_{x_{min}}^{x_{max}} \int_{y_{lower}(x)}^{y_{upper}(x)} 2ye^x \, dy \, dx \]
Without the specific limits of integration, we cannot proceed with an actual calculation. However, the process involves evaluating the inner integral with respect to y, and then the outer integral with respect to x.
The complete question is: Calculate the double integral of f(x, y) over the triangle indicated in the following figure: y 4 3 2 1 f(x, y) = 12yet X 1 2 3 4 5