Question

Consider the following function:

def squareArea(sideLength) :
return sideLength ** 2
What is the value of squareArea(squareArea(2))?

Answer 1

The value of squareArea(squareArea(2)) is: 16

Let's break down the expression 'squareArea(squareArea(2))' step by step.

'squareArea(2)': This calls the 'squareArea' function with an argument of 2. The function calculates the square of 2, which is 4.

'squareArea(squareArea(2))': Now, we need to find the value of 'squareArea' with the argument being the result of the previous step, which is 4. So, it becomes 'squareArea(4)'.

'squareArea(4)': This calls the 'squareArea' function with an argument of 4. The function calculates the square of 4, which is 16.

Therefore, the value of 'squareArea(squareArea(2))' is 16.

Complete Question:
Consider the following function:
def squareArea(sideLength) :
return sidelength ∗∗2
What is the value of squareArea(squareArea(2))?
a. 2

b. 4

c. 8
d. 16

Answer 2

The calculated value of squareArea(squareArea(2)) is 16.

What is the value of squareArea(squareArea(2))?

From the question, we have the following parameters that can be used in our computation:

def squareArea(sideLength):

return sideLength ** 2

This function defines the area of a square given the side length. It takes one argument, sideLength, and returns the area of the square.

This line of code calls the squareArea function twice.

First, it calls squareArea(2), which calculates the area of a square with a side length of 2.

This returns 4.

Then, it calls squareArea(4), which calculates the area of a square with a side length of 4. This returns 16.

So, the value of squareArea(squareArea(2)) is 16.