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The equation (2x+1)^2= -2 has ___ real solutions

User CallumVass
by
7.8k points

1 Answer

4 votes

Answer: Zero

Explanation:

To find how many real solutions this equation has, we will solve.

Given:

(2x + 1)² = -2

Square root of both sides of the equation:

2x + 1 = ±
√(-2)

Subtract 1 from both sides of the equation:

2x = ±
√(-2) - 1

Divide both sides of the equation by 2;

x = ±
(√(-2)-1 )/(2)

Simplify the square root:

x = ±
(i√(2)-1 )/(2)

There are no real solutions to this equation.

User Andybauer
by
8.5k points

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