Answer:
The electrolysis of AgCl results in the formation of silver (Ag).
The balanced chemical equation for the reaction is:
AgCl --> Ag + Cl
From the balanced equation, it's clear that one mole of AgCl gives one mole of Ag. According to the periodic table, the molar mass of AgCl is approximately 143.32 g/mol and the molar mass of Ag is 107.87 g/mol.
Therefore, from stoichiometry, the mass of Ag that can be obtained from 1 g of AgCl is (107.87 g/mol) / (143.32 g/mol).
So, from 30 g of AgCl, the mass of Ag that can be deposited is 30 * (107.87 g/mol) / (143.32 g/mol) = 22.57 g.
Therefore, approximately 22.57 grams of Silver can be deposited from the electrolysis of 30g AgCl.