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The sum of three consecutive integers is -126​

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Answer:

-43, -42, -41

Explanation:

Solving algebraic equations:

Let the three consecutive integers by x, x + 1, x + 2.

The sum three consecutive integers is -126.

x + x +1 + x + 2 = -126

x + x + x + 1 + 2 = -126

Combine like terms,

3x + 3 = -126

Subtract 3 from both sides,

3x = -126 -3

3x = -129

Divide both sides by 3,

x = -129 ÷ 3


\boxed{\bf x = -43}

x + 1 = -43 +1

When two integers are different sign, subtract and the result will have the bigger number sign. Here, the bigger number has a negative sign and so, the resultant number is -42.

= -42

x + 2 = -43 + 2

= - 41

Answer: Three consecutive integers are -43, -42, -41

User Roy Peleg
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