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Describe the possible echelon forms of the standard matrix for a linear transformation T where​ T: ℝ3→ℝ4 is​ one-to-one.

User Xiaoye
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Answer:║Y * * ║║0 Y * ║║0 0 Y║║0 0 0║

Step-by-step explanation:mFirst, let's look at the information in the question:The proof of the theorem proves that the columns, say, A and B must be independent. In the matrix, there is linearity and the trivial solution would be [ 0, 0 , 0 , 0] for the matrix to exist. In other words, all the unknowns must be zero.This establishes the fact that the matrix T needs to be independent for the matrix function, say T (x) to be one-to-one. By definition, one-to-one is ker (T) = {0}Thus, the null space is occupied only by the zero vector. Note: if there was no linear independence in the vectors, the solution would not be zero in the vector.

User Mouradif
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