Question

If 3.0 l of helium at 20.0°c is allowed to expand to 4.4 l, with the pressure remaining the same, what is the new temperature? select one: a. 702 k b. - 30.0°c c. 430 k d. 29.3°c

Answer 1

We should use Charles's law. By plugging the given values into the formula and solving for T2, we find that the new temperature of the helium is 430 K, which is answer choice 'C: 430 K'. Therefore the correct option is C.

Step-by-step explanation:

To solve this, we employ the principle of Charles's law, which holds that the volume of a gas is directly proportional to its absolute temperature if pressure is held constant. We first need to convert the temperature given from Celsius to Kelvin, because gas laws operate on absolute (Kelvin) scales. Thus, 20°C converts to 293K.

The equation for Charles's law is V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature and V2 and T2 are the final volume and temperature. Plug the given data into the equation:

(3.0 L/293 K) = (4.4 L/T2)

Solving for T2, we get: T2 = 4.4L * 293 K / 3.0 L

T2 = 430 K, so the correct answer is C: 430 K.

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