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Given f(x) = sqrt (3x-12) 2 what is the range in set notation?y ∈ r, y ≥

User Estel
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Final answer:

The range of the function f(x) = √(3x-12)^2 in set notation is y .

Step-by-step explanation:

The range of a function represents the set of all possible output values. To find the range of the function f(x) = √(3x-12)^2, we need to consider the possible values of (3x-12)^2. Since the square of a number can never be negative, the function will only output non-negative values. Therefore, the range in set notation is y ∈ ℝ, y ≥ 0.

User Rjanjic
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