Answer: 95%
Step-by-step explanation
mu = 65 = mean
sigma = 4 = standard deviation
Compute the z score when x = 57
z = (x - mu)/sigma
z = (57 - 65)/4
z = -8/4
z = -2
Repeat for x = 73 and you should get z = 2
This tells us P(65 < x < 73) is equivalent to P(-2 < z < 2) for the mu and sigma values mentioned.
According to the Empirical Rule, roughly 95% of the normally distributed data values are within 2 standard deviations of the mean. In terms of symbols we write P(-2 < z < 2) = 0.95 approximately.
Furthermore, P(65 < x < 73) = 0.95 approximately when mu = 65 and sigma = 4.
About 95% of the vehicles have speeds between 57 mph and 73 mph.