Final answer:
The volume of 19.87 mol of ammonium chloride at STP is 445.088 L. Therefore, the correct option is B
Step-by-step explanation:
The volume of a given amount of substance at STP (standard temperature and pressure) can be calculated using the ideal gas law equation: PV = nRT. In this equation, P represents pressure, V represents volume, n represents the number of moles of the substance, R is the ideal gas constant, and T represents temperature. At STP, the pressure is 1 atm and the temperature is 273.15 K.
To find the volume, we need to rearrange the equation to isolate V. Since we are given the number of moles (19.87 mol) and all the other variables are known, we can substitute them into the equation and solve for V. Plugging in the values:
V = nRT/P = (19.87 mol)(0.0821 L·atm/mol·K)(273.15 K)/(1 atm)
= 445.088 L.
Therefore, the volume of 19.87 mol of ammonium chloride at STP is 445.088 L. The correct answer is option b.
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