If X and Y are mutually exclusive events with P(X) = 0.285, P(Y) = 0.34, then P(X ∩ Y) = _____. a. 1 b. 0 c. 0.097 d. 0.715

asked Jun 22, 2024 62.0k views

2 votes

If X and Y are mutually exclusive events with P(X) = 0.285, P(Y) = 0.34, then P(X ∩ Y) = _____.

a. 1
b. 0
c. 0.097
d. 0.715

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1 vote

If they're mutually exclusive then
$P(A\cap B)=P(A)\cdot P(B)$ .

Therefore

$P(A\cap B)=0.285\cdot 0.34=0.0969\approx0.097$

Jonplaca answered Jun 27, 2024