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3x^2 + 3y^2 − 18x − 6y − 18 = 0 is the equation of a circle with center ( h , k ) and radius r for:
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3x^2 + 3y^2 − 18x − 6y − 18 = 0 is the equation of a circle with center ( h , k ) and radius r for:

User Rdubya
by
8.1k points

1 Answer

6 votes

Answer:

Hi,

Explanation:

Making square:


3x^2+3y^2-18x-6y-18=0\\\\x^2+y^2-6x-2y-6=0\\\\x^2-6x+9+y^2-2y-6-9-1=0\\\\(x-3)^2+(y-1)^2=4^2\\\\center\ is\ (3,1)\\radius\ is \ 4\\

User Navid Abutorab
by
8.0k points
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