Question

Solve the following system algebraically.

y = x2 + 11 and y = –12x


A. (12, –11) and (132, –1)

B. (132, 12) and (–11, –1)

C. (12, 132) and (–1, –11)

D. (–11, 132) and (–1, 12)

Answer 1

option C:

(12, 132) and (-1, -11)

Explanation:

y = x² + 11 and y = -12x

x² + 11 = -12x

x² + 12x + 11 = 0

x² + 11x + x + 11 = 0

x(x + 11) + 1(x + 11) = 0

(x + 1)(x + 11) = 0

x = -1 and x = -11

by substituting values of x to find y,

y = (-1)² + 11 and y = -12(-11)

y = 1 + 11 and y = 132

y = 12 and y = 132