Answer:
1.0 × 10⁻⁸ mol/L
Step-by-step explanation:
Calculating pH & pOH
We're given:
- [OH-] = 1.0 × 10⁻⁶ mol/L
- [H+] = ?
Determine pOH:
pOH = -log[OH-]
pOH = -log[1.0 × 10⁻⁶ mol/L]
pOH = 6
Determine pH:
pH = 14 - pOH
pH = 14 - 6
pH = 8
Determine [H+]:
pH = -log[H+]
8 = -log[H+]
[H+] = 10⁻⁸ mol/L