Question

A father is four times as old as his son. In 20 years time the father will be twice as old as his son. Determine the age of the son & dad at the time of this question.​

Answer 1

father = 40 ; son = 10

Explanation:

f = father

s = son

f = 4s

f + 20 = 2 ( s + 20)

4s + 20 = 2s + 40

4s - 2s = 40 - 20

2s = 20

2/2 s = 20/2

s = 10

f = 4 · 10 = 40